NEC - Cable Size Under Short Circuit Calculation
- Last UpdatedJul 14, 2025
- 4 minute read
This section describes the fault current calculation that needs to be performed after the cable has been sized.
The adiabatic method shown below calculates maximum short circuit current. The larger the cable, the larger the current the cable can withstand without damage
Similar to the other standards it starts with source impedance from the equipment types:
-
Transformer (Windings)
-
Source
-
Generator
For transformers, infinite primary short-circuit current is assumed to be used (known as infinite bus).
Step – I Calculate Full Load Current (IFLC)
IFLC = (Er * 1000)
V
Where:
IFLC = Full Load current in Amps
V = Phase voltage (Vph * Ö3/2) for 1 phase, Line voltage Vl for 2 phase or Line voltage (Vl * Ö3) for 3 phase
Er = Equipment rating with units in kVA
Step – II Calculate Transformer Multiplier Factor (MTR)
MTR = (100)
(Imp %)
Where:
MTR = Transformer multiplier
Imp % = Equipment Impedance expressed as a percentage
Step – III Calculate Short Circuit Current due to Source (ISC)
ISC = IFLC * MTR
Where:
ISC = Short Circuit current in Amps
IFLC = Full Load current in Amps
MTR = Transformer multiple
Steps I to III are used to calculate the short circuit due to source.
Step – IV Calculate F Factor
This section describes how the short circuit is calculated at each level rather than calculating the impedance.
This considers the calculating factor "F" of each cable for each number of phases.
-
Condition: If No of Phases = 3 and cable length in feet
f = Ö3 * ISCa * Zc
Pn * V
Where:
L = length of conductor in feet
ISCa = available short-circuit current in amps at beginning of circuit
Zc = conductor impedance in Ohms
Pn = number of conductors in parallel
V = Line voltage
Or
-
Condition: If No of Phases = 3 and cable length in Meter
f = Ö3 * ISCa * Zc
Pn * V
Where:
L = length of conductor in meter
ISCa = available short-circuit current in amps at beginning of circuit.
Zc = conductor impedance in ohms
Pn = number of conductors in parallel
V = Line voltage
-
Condition: If No of Phases = 2 and cable length in feet
f = 2 * ISCa * Zc
Pn * V
Where:
L = length of conductor in feet
ISCa = available short-circuit current in amps at beginning of circuit.
Zc = conductor impedance in Ohms
Pn = number of conductors in parallel
V = Line voltage
Or
-
Condition: If No of Phases = 2 and cable length in Meters
f = 2 * ISCa * Zc
Pn * V
Where:
L = length of conductor in meters
ISCa = available short-circuit current in amps at beginning of circuit
Zc = conductor impedance in Ohms
Pn = number of conductors in parallel
V = Line voltage
-
Condition: If No of Phases = 1 and cable length in feet
f = 2 * ISCa * Zc
Pn * V
Where:
L = length of conductor in feet
ISCa = available short-circuit current in amps at beginning of circuit.
Zc = conductor impedance in Ohms
Pn = number of conductors in parallel
V = Line voltage
Or
-
Condition: If No of Phases = 1 and cable length in Meters
f = 2 * ISCa * Zc
Pn * V *
Where:
L = length of conductor in meters
ISCa = available short-circuit current in amps at beginning of circuit
Zc = conductor impedance in Ohms
Pn = number of conductors in parallel
V = Line voltage
Step – V Calculate Impedance (Zc)
If impedance values (resistive and reactive components) are available from cable catalogue
Or
If NEC Table 9 values available
Or
If NEC Table 9 does not have sizes, then use this equation:
Zc = (L/1000) * Ö[(Rc)2 + (Xc)2])
Where:
Rc is resistance of active conductor (Ohms/m)
Xc is reactance of active conductor (Ohms/m)
Or
Zc = (L/1000) * Ö[(Rc)2 + (Xc)2])
Where:
Rc is resistance of active conductor (Ohms/ft)
Xc is reactance of active conductor (Ohms/ft)
Step – VI Calculate Short Circuit
ISC = ISCa * 1
(1 + f)
Where:
f = factor
ISC = Short Circuit current in Amps
ISCa = Supply short-circuit current in Amps
Step – VII Calculate cable size under Short Circuit Condition
From ICEA P-32-382, the equation to calculate the minimum conductor cross-sectional area is as follows:
-
Condition - For Material = Copper
A = Ö[((IAD/P)2 t)/(0.0297log10 [(Tf + 234) / (Ti + 234)])]
-
Condition - For Material = Aluminium
A = Ö[((IAD/P)2 t)/(0.0125log10 [(Tf + 228) / (Ti + 228)])]
Where:
IAD = short-circuit current in Amperes
t = duration of short-circuit (s)
A = conductor cross-sectional area in circular mils
Tf = final temperature (°C)
Ti = initial temperature (°C)
log10 = log 10
P = number of conductors in parallel
Note:
The option for this value is set in the project options. The options are to use Conductor
Temperature for the cable or the calculated operating temperature.

The maximum short circuit temperature (Tf) values can be found:
|
Max Cable Op. Temp |
Max Short Circuit Temp Tf |
|---|---|
|
60 |
150 |
|
75 |
150 |
|
80 |
250 |
|
90 |
250 |
|
150 |
250 |
|
200 |
250 |
|
250 |
350 |
NEC Table 8 shows the relationship between cable size in standard units and circular mil.