Repetition Effects
- Last UpdatedDec 03, 2025
- 1 minute read
It is possible to treat several (maximum 25) components (stiffeners, holes, ) in one statement by assigning a number of values to one or more keywords (or by using several references). Then the rules explained by the example below must be followed.
Suppose that n components (say holes) shall be generated in one statement. Then the number of assigned values for each keyword, must equal to one of the following values
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1. |
= 0 |
In this case, the default value will be used for all n holes. |
|
2. |
= 1 |
The single value assigned will be valid for all holes. |
|
3. |
= n |
Each of the n holes will have one value of its own. |
A violation of this rule will normally cause an error.
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Example: |
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HOLE, D500, U = FR76, FR79, V = 1000; |
Two holes will be set, located at frames 76 and 79, respectively. Both holes will be set at the v-coordinate 1000 (since only one value is assigned to V). The default value (=0) for inclination will be used (T is assigned no value at all).
Note: The number of allowed values is specific to each combination of keyword and statement.