Example
- Last UpdatedNov 28, 2025
- 2 minute read
Below you will find the selection row for endcut type 22 followed by the parameter row for endcut code 2211.
|
Type |
A |
B |
C |
R1 |
R2 |
V1 |
V2 |
V3 |
V4 |
||
|
601 |
22 |
9 |
10 |
1021 |
-1 |
1 |
-1 |
100 |
202 |
-1 |
-1 |
|
... |
|||||||||||
|
601 |
2211 |
2 |
35 |
30 |
|||||||
|
... |
Suppose that the stiffener end has been generated by the following input:
CUT = 2211, 150, 50, 80(*) (* Normally calculated automatically)
The result will be as shown in Figure 6:3 below.
Figure 6:3. Explicit parameters for creation of endcut type 22
|
A |
(Selection code = 10, that means, X=0, Y=0, Z=1, W=0). Since Z=1, set A = acut (150) |
|
B |
(Selection code = 1021). First set B = bcut (=50). Since B now has a value, disregard the value indicated by W (and X). (If bcut had been zero, then B would have been set equal to R1 (=35)). |
|
C |
= 0 (Selection code = -1) |
|
R1 |
(Selection code = 1). Set R1 to parameter value number 1 in parameter row (=35) |
|
R2 |
= 0 (Selection code = -1) |
|
V1 |
(Selection code = 100). Since Y=1 set V1 = a1 (=80). Since X=0 no further change. |
|
V2 |
(Selection code = 202). Since W=2, set V2 equal to second parameter of parameter row (30). Since the value of V2<90 V2 will not be affected by the condition Y=2. |
|
V3 |
= 0 (Selection code = -1) |
|
V4 |
= 0 (Selection code = -1) |
If a customer wants to change one of the standard values, he should proceed like this:
-
Identify the parameter you want to change (suppose for example, that you want to change V2 from 30 to 45 degrees).
-
Examine the last digit of the selection code for that parameter (in this case 202). Look up parameter 2 in the parameter row for endcut code 2211 and change 30 to 45.